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There were mostly correct answers provided in POTW #29. Out of the first 160 beads, there were in fact 50 blue beads. If you obtained a different answer, try to see how and where you may have errored.
Square ABCD is 25cm2 I used the Pythagorean theorem to find the length of one side of the square (i.e line segment AB) I know a pythgoran triangle can have angles 3 4 and 5, meaning that AB is 5. The area of a square is length times width so 5x5. Therefore the area is 25cm2
First I used the pythagorean theorem to find the line segment BC. 4x4=16 3x3=9 9+16=25 x*x=25 x=5 5x5=25 5units is the side length. 5x5=25. The area is 25 units squared.
3 x 3 = 9 4 x 4 = 16 9 + 12 = 21 Square root of 21 = 4.58 (Rounded up to 5) 5 units = side length of square. 5 X 5 = 25 The area of square ABCD is 25 squared units.
I used the pythagorean theorem to find line segment to find line segment BC 4^2 = 16 3^3 = 9 16+9= 25 BC^2= 25 BC=5 BC* AB = area of square and since it's a square BC and AB are the same so it's really: 5*5= 25 the area of the square is 25 units squared.
I did my work hard copy but I did retrieve an answer of 25 units squared for the area of square ABCD.
ReplyDeleteSquare ABCD is 25cm2
ReplyDeleteI used the Pythagorean theorem to find the length of one side of the square (i.e line segment AB)
I know a pythgoran triangle can have angles 3 4 and 5, meaning that AB is 5.
The area of a square is length times width so 5x5.
Therefore the area is 25cm2
I did my work hard copy and got 25 units for the area of the square.
ReplyDelete3x3 = 9
ReplyDelete4x4 = 12
12+9=21
square root =4.58 = 5 rounded x 2 = 25
The area of the square is 25 units.
My work was done hard copy, obtaining the answer of 25 units squared.
ReplyDeleteSquare ABCD has an area of 25 units squared, hard copy.
ReplyDeleteFirst I used the pythagorean theorem to find the line segment BC.
ReplyDelete4x4=16
3x3=9
9+16=25
x*x=25
x=5
5x5=25
5units is the side length.
5x5=25.
The area is 25 units squared.
3 x 3 = 9
ReplyDelete4 x 4 = 16
9 + 12 = 21
Square root of 21 = 4.58 (Rounded up to 5)
5 units = side length of square.
5 X 5 = 25
The area of square ABCD is 25 squared units.
I did it hard copy and found that the square was 25 units squared
ReplyDeleteI did it hard copy. the area of square ABCD is 25 units squared.
ReplyDeleteI used the pythagorean theorem to find line segment to find line segment BC
ReplyDelete4^2 = 16
3^3 = 9
16+9= 25
BC^2= 25
BC=5
BC* AB = area of square and since it's a square BC and AB are the same so it's really:
5*5= 25
the area of the square is 25 units squared.