This blog is the online extension of our intermediate classrooms. Our goal is to enhance and document our learning experience throughout the school year, and share this journey with teachers, parents and students. We welcome your constructive feedback, and we look forward to learning with you!
POTW 7/8 Possible Answer: 2 Variety Pack Bs, 4 Variety Pack As (total cost of $26.10) 4 x 2 = 8 Milk 2 x 2 = 4 Dark 3 x 2 = 6 White 2 x 4 = 8 + 8 = 16 Milk 1 x 4 - 4 + 4 - 8 Dark It follows requirements of exactly the correct number of chocolates. I don't know how to explain how this is correct in a good way, but pack C gives 2 Milk, 1 Dark, 3 White. Pack B gives 4 Milk, 2 Dark, 3 White. 2 pack Cs is equivalent to the same number of Dark and Milk, but not White. White has 3 more and would be finished. It'll also cost more money ($4.55 x 2 = $9.10 is more than $7.65). From there, to get an EXACT amount, no more whites can be purchased and you need 12 more milk and 6 more dark. It'll have to come from pack A. $2.70 x 6 (2 x 6 = 12, 1 x 6 = 6) = $16.20 + $9.10 = $25.30 From there, $25.30 is smaller than $26.10. So the answer is actually not what was previously said. Possible Answer: 2 Variety Pack Cs, 6 Variety Pack As ($25.30) That isn't explained well at all, but this is the answer due to those calculation, or is it? 1 Variety Pack C, 1 B, 5 As will end in the perfect number as well, except the final cost is $25.70, more than $25.30. These are all the possibilities allowed. Just 3????? (Yes) Answer: 2 Variety Pack Cs, 6 Variety Pack As ($25.30) Mr. Gee should buy 2 Variety Pack Cs and 6 Variety Pack As to get exactly the correct number of chocolate bars for the lowest price.
POTW: I'm gonna have to test some of these cases out. First of all, I realized that buying one B is the same as buying a variety pack A and C. So, which one is more worth it? I add up A and C which is 2.70+4.55 = $7.25, which is less than B, which is $7.65. This means that I would rather buy A and C together than B. So, I would do that. Each variety pack C has 3 white chocolates, and there are 6 students, so I divide 6 by 3, giving me 2, which shows that Mr. Gee will buy 2 packs of Variety C. Then, because I have dark chocolate and milk chocolate bars as well I calculate that, giving me 4 milk and 2 dark chocolate bars. That means that there are 12 milk and 6 dark chocolates left to buy, which I use Variety A for. Because each one is 2 milk and 1 dark chocolate, I can divide it and it will give me 6 packs of Variety A.
Overall, this will be 6 packs of Variety A, no packs of variety B, and 2 packs of Variety C. This will be a total of 16.2+9.1 = $25.30. I may reply to this comment if I miscalculated somewhere. -Alan
Info: - 16 MILK - 8 DARK - 6 WHITE (Fun Fact: White chocolate isn't a chocolate. It doesn't have the chocolate solids) - Pack A: 2.70 and 2 MILK 1 DARK - Pack B: 7.65 and 4 MILK 2 DARK 3 WHITE - Pack C: 4.55 and 2 MILK 1 DARK 3 WHITE
Pack A seems decent as it has a decent amount of bars and it isn't as expensive as B. Pack B seems like the best pack to buy, since it contains a lot of chocolate bars, but it is expensive. Pack C has about half of what Pack B has, but costs more than half of Pack B.
Buying one pack B would be the same as buying one A and one C. It has the same amount of bars. But, it would cost only 7.25 compared to B's 7.65. So buying 1 Pack A and 1 Pack C would be the better choice than one B. Now, I need to figure out how many packs can be bought, giving 16 MILK, 8 DARK and 6 WHITE. Buying one Pack C: Need: 14 MILK 7 DARK, 3 WHITE left to buy. Buying another Pack C: Need: 12 MILK 6 DARK 0 WHITE. If another Pack C is bought, then the white chocolate bars that are not needed would go to waste. Since Pack A is the only one that comes with MILK and DARK without any WHITE, multiple Pack As can be bought. Since there are 12 MILK left and each pack comes with 2, then 6 packs have to be bought which is convinent because 6 DARK have to be bought and each pack comes with 1. Buying 6 Pack A: Need: 0 MILK 0 DARK 0 WHITE. Now we need to find the cost of 2 Pack C and 6 Pack A. The cost would be 16.20+9.1=25.30 6 Pack A should be bought and 2 Pack C should be bought, costing a total of $25.30.
so here's what I got: 6 packs of A and 2 packs of C.
I could already see that I wouldn't really use Pack B since it's expensive compared to how much you actually get. Pack A is probably going to be the most effective pack since three of pack A is approximately the same as pack B expect you get more out of it. Using pack A and pack C ended up going pretty well together which I wasn't expecting. if I just get 2 pack C's, I would already have enough white chocolate, 4 white chocolate and 2 dark chocolate. The two packs go well together because to get the rest of the chocolate, all I need is 6 pack A's and I would get enough chocolate. I don't really need to show how other options wouldn't work since I know pack B is just not that great of a deal.
16 milk choc 8 dark choc 6 white choc Get 2 variety pack Cs, 6 variety pack As, which will add up to 25.30. This is the lowest price is 25.30 by getting 6 packs of A and 2 packs of C. B is expensive so just get 2 packs of C to get enough white chocolate bars, and getting the rest from pack As are cheaper than getting pack Cs.
POTW #14: I did the work on a scrap piece of paper. Also, Happy New Year! In order for Mr. Gee to fulfill his student's requests for Valentine's Day at the lowest price possible, he should buy 6 Variety Pack As and 2 Variety Pack Cs.
POTW 7/8
ReplyDeletePossible Answer: 2 Variety Pack Bs, 4 Variety Pack As (total cost of $26.10)
4 x 2 = 8 Milk
2 x 2 = 4 Dark
3 x 2 = 6 White
2 x 4 = 8 + 8 = 16 Milk
1 x 4 - 4 + 4 - 8 Dark
It follows requirements of exactly the correct number of chocolates.
I don't know how to explain how this is correct in a good way, but pack C gives 2 Milk, 1 Dark, 3 White. Pack B gives 4 Milk, 2 Dark, 3 White. 2 pack Cs is equivalent to the same number of Dark and Milk, but not White. White has 3 more and would be finished. It'll also cost more money ($4.55 x 2 = $9.10 is more than $7.65). From there, to get an EXACT amount, no more whites can be purchased and you need 12 more milk and 6 more dark. It'll have to come from pack A. $2.70 x 6 (2 x 6 = 12, 1 x 6 = 6) = $16.20 + $9.10 = $25.30
From there, $25.30 is smaller than $26.10. So the answer is actually not what was previously said.
Possible Answer: 2 Variety Pack Cs, 6 Variety Pack As ($25.30)
That isn't explained well at all, but this is the answer due to those calculation, or is it?
1 Variety Pack C, 1 B, 5 As will end in the perfect number as well, except the final cost is $25.70, more than $25.30. These are all the possibilities allowed. Just 3????? (Yes)
Answer: 2 Variety Pack Cs, 6 Variety Pack As ($25.30)
Mr. Gee should buy 2 Variety Pack Cs and 6 Variety Pack As to get exactly the correct number of chocolate bars for the lowest price.
POTW:
ReplyDeleteI'm gonna have to test some of these cases out.
First of all, I realized that buying one B is the same as buying a variety pack A and C. So, which one is more worth it? I add up A and C which is 2.70+4.55 = $7.25, which is less than B, which is $7.65. This means that I would rather buy A and C together than B. So, I would do that. Each variety pack C has 3 white chocolates, and there are 6 students, so I divide 6 by 3, giving me 2, which shows that Mr. Gee will buy 2 packs of Variety C. Then, because I have dark chocolate and milk chocolate bars as well I calculate that, giving me 4 milk and 2 dark chocolate bars. That means that there are 12 milk and 6 dark chocolates left to buy, which I use Variety A for. Because each one is 2 milk and 1 dark chocolate, I can divide it and it will give me 6 packs of Variety A.
Overall, this will be 6 packs of Variety A, no packs of variety B, and 2 packs of Variety C. This will be a total of 16.2+9.1 = $25.30. I may reply to this comment if I miscalculated somewhere.
-Alan
This comment has been removed by the author.
DeleteInfo:
ReplyDelete- 16 MILK
- 8 DARK
- 6 WHITE (Fun Fact: White chocolate isn't a chocolate. It doesn't have the chocolate solids)
- Pack A: 2.70 and 2 MILK 1 DARK
- Pack B: 7.65 and 4 MILK 2 DARK 3 WHITE
- Pack C: 4.55 and 2 MILK 1 DARK 3 WHITE
Pack A seems decent as it has a decent amount of bars and it isn't as expensive as B. Pack B seems like the best pack to buy, since it contains a lot of chocolate bars, but it is expensive. Pack C has about half of what Pack B has, but costs more than half of Pack B.
Buying one pack B would be the same as buying one A and one C. It has the same amount of bars. But, it would cost only 7.25 compared to B's 7.65. So buying 1 Pack A and 1 Pack C would be the better choice than one B.
Now, I need to figure out how many packs can be bought, giving 16 MILK, 8 DARK and 6 WHITE.
Buying one Pack C:
Need:
14 MILK 7 DARK, 3 WHITE left to buy.
Buying another Pack C:
Need:
12 MILK 6 DARK 0 WHITE.
If another Pack C is bought, then the white chocolate bars that are not needed would go to waste. Since Pack A is the only one that comes with MILK and DARK without any WHITE, multiple Pack As can be bought. Since there are 12 MILK left and each pack comes with 2, then 6 packs have to be bought which is convinent because 6 DARK have to be bought and each pack comes with 1.
Buying 6 Pack A:
Need:
0 MILK 0 DARK 0 WHITE.
Now we need to find the cost of 2 Pack C and 6 Pack A.
The cost would be 16.20+9.1=25.30
6 Pack A should be bought and 2 Pack C should be bought, costing a total of $25.30.
No wonder why my favorite overall chocolate is white chocolate!
DeleteAh, nice eye Fiona!
Deleteso here's what I got: 6 packs of A and 2 packs of C.
ReplyDeleteI could already see that I wouldn't really use Pack B since it's expensive compared to how much you actually get. Pack A is probably going to be the most effective pack since three of pack A is approximately the same as pack B expect you get more out of it. Using pack A and pack C ended up going pretty well together which I wasn't expecting. if I just get 2 pack C's, I would already have enough white chocolate, 4 white chocolate and 2 dark chocolate. The two packs go well together because to get the rest of the chocolate, all I need is 6 pack A's and I would get enough chocolate. I don't really need to show how other options wouldn't work since I know pack B is just not that great of a deal.
16 milk choc
ReplyDelete8 dark choc
6 white choc
Get 2 variety pack Cs, 6 variety pack As, which will add up to 25.30. This is the lowest price is 25.30 by getting 6 packs of A and 2 packs of C. B is expensive so just get 2 packs of C to get enough white chocolate bars, and getting the rest from pack As are cheaper than getting pack Cs.
Grade 8 POTW
ReplyDeleteMr. Gee should purchase 2 of Variety Pack C and 6 of Pack A. I did my work on paper.
Mr.Gee should get 6 VPA and 2 VPC. Work on gapps. VP=Variety Pack
ReplyDelete6 Variety pack A's and 2 Variety pack C's would provide the essential numbers of chocolate, with a price of $25.30.
ReplyDeleteGrade 8 POTW:
ReplyDeleteMr. Gee should buy 6 from Variety Pack A and 2 from Variety Pack C. My work is done in my math notebook.
Mr. Gee should get 2 VPC and 6 VPA. (Sorry for doing it late + did in my notebook)
ReplyDeleteMr. Gee should should buy 6 Variety Pack A's and 2 Variety Pack C's. Work is done on paper.
ReplyDeleteMr. Gee should buy 6 Variety Pack As, 0 Variety Pack Bs, and 2 Variety pack Cs. This would give him a total of $25.30.
ReplyDeleteP.S. Sorry about the short explanation. I had written a full explanation about a week ago but accidentally closed the tab.
POTW #14:
ReplyDeleteI did the work on a scrap piece of paper. Also, Happy New Year!
In order for Mr. Gee to fulfill his student's requests for Valentine's Day at the lowest price possible, he should buy 6 Variety Pack As and 2 Variety Pack Cs.
POTW #14:
ReplyDeleteInfo:
16 Milk, 8 Dark and 6 White
Combo #1: 6 Pack A and 2 Pack C
This looked, at first glance the most affordable.
Price: $25.30
Then I tried another Combo:
2 Pack Bs and 4 Pack As
The price was greater.
Price: $26.10
Finally, I tried One pack B and C and five pack As
Price: $25.70
These were all the combos I found that gave the exact amount of chocolate Mr.Gee needed.
The lowest and equal amount Mr.Gee should get from the store are 6 pack As and 2 pack Cs.