Thursday, November 19, 2015

POTW #12 - Irregular Shapes

Please see the solution for POTW #11 below and POTW #12 follows after that:



POTW #12

22 comments:

  1. If you did not obtain the answer of 212 for POTW #11 please check your work, the solution, and your peers' work to see why.

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  2. The area of this irregular trapezoid is 17.5 units squared. How I got this answer was that I first looked for what kind of irregular shape this was. It was a trapezoid. From my background knowledge from class the area of a trapezoid is (b1+b2)/2xh. So I found the height, base 1 and base 2.
    Height = 5 units
    Base1 = 3 units
    Base2 = 4 units
    Then I plugged the numbers into the formula.
    (3+4)/2x5
    3+4=7
    7/2=3.5
    3.5 x 5 = 17.5
    Thus the area is 17.5 units squared.

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    Replies
    1. The top base is actually 2 units so the answer would actually be 15 units,

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  3. To simply solve this problem, I found both the realistic measurement and theoretical measurements. The realistic answer would be 1.05714285714 units squared. The theoretical area is 1.2 units squared.

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  4. To find the area, I used the formula. For the area of a trapezoid, the formula is: ((Base 1 + Base 2) ÷ 2) x Height. In the question, it states that the distance between each dot (vertically and horizontally) is one unit, and therefore, the difference between diagonal dots must also be one unit. So, the measurements are:
    Bottom Base(Base 1) - 4 units
    Top Base(Base 2) - 2 units
    Height - 5 units
    Next, I plugged these numbers back into the formula. resulting in: ((4 + 2) ÷ 2) x 5.
    When I calculated the formula, the answer I got was 15. Therefore, the area of this trapezoid is 15 squared units.

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  5. I know the formula to find the area of a trapezoid is base + base /2 x height = area.
    The bases equal 6; 4+2=6
    6/2 = 3 Now me now the average of the bases
    Multiplied by 5 which is the height makes 15; 3 x 5 = 15
    Since the dots on the diagram are one unit apart vertically and horizontally, that makes the area of the trapezoid 15units2.

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  6. I see a variety of different answers here. I wonder which could be proven most effectively?

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  7. Let a = base 1 Let b = base 2 Let h = height
    A(trapezoid)=((a+b)/2)h
    A = ((2+4)/2)5 = 15
    The area of the trapezoid is 15 units squared

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  8. Avg. length of parallel sides
    2 + 4 = 6
    6/2 = 3
    Length multiplied by height (rel. to 90 degrees)
    5 x 3 = 15 units.
    The area is 15 square units

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  9. The two bases are 4 cm and 2 cm. Therefore, you have to add them and divide by 2.
    (2+4)/2=3 cm
    The height is 5 cm so you have to multiply the average which is 3 cm to 5 cm to get the area of the trapezoid or irregular shape.
    5*3=15 cm 2
    Therefore, the area of this trapezoid or irregular shape is 15 cm 2 (fifteen squared centimeters)

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  10. First I found all the perimeters. The bottom is 4, the top is 2, the left side is 5. This shape is a irregular trapezoid, so assumed that I would have to use the normal trapezoid formula, which is: (B1 + B2) / 2 * H.
    So, now I replaced all the variables with the correct numbers, which became: (4 + 2) / 2 * 5. Then I solved that equation, and got: 15.
    The area of this irregular trapezoid is 15 units 2.

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  11. I got 15cm2 for my answer. I did this by using the formula B1+B2/2 x Height= Area, and inputted values:
    2+4/2 x 5cm
    6cm/2 x 5cm.
    3cm x 5cm
    15cm2.

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  12. Here is how I solved the problem:
    Base 1 = 4 units
    Base 2 = 2 units
    Height = 5 units
    Since this is a trapezoid the formula for area is ((B1 + B2)/2) * H you would have to do;
    ((4+2)/2) * 5
    (6/2) * 5
    3 *5 = 15
    The area of this figure is 15 units squared.

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  13. To find the area of this irregular shape I must divide it up into two smaller parts, a rectangle and a small triangle.
    The rectangle's dimensions are 6 by 3 units.
    6x3=18 units2.
    The triangle's dimensions are 6 by 2 divided by 2
    6x2/2=6 units2.
    18+6=
    Therefore the area of the shape is 24 units2.

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  14. The area of the trapezoid is 15 units2. To find the area, you use the formula for finding area of a trapezoid which is (a+b)h/2. The 2 bases (a and b) are parallel to each other which means their side lengths are 2 and 4 units (the length of the parallel sides on the trapezoid). The trapezoid also has a right angle, which means we can use the height is just the length of a side. So I inputted these numbers into the formula:
    A=(a+b)h/2
    A=(2+4)5/2
    A=6*5/2
    A=30/2
    A=15 units2
    Therefore the area of the trapezoid is 15 units2

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  15. The shape shown resembles the attributes of a trapezoid - 1 pair of parallel sides & 4 sides total.
    The formula for finding the area of a trapezoid is (b1+b2)/2 x h...
    A= 2 + 4/ 2 x 5
    = 6/2 x 5
    = 3 x 5
    = 15
    The area of the irregular trapezoid is 15cm2

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  16. Height = 5
    B1 = 4
    B2 = 2
    ((B1 + B2) / 2) x Height = Area
    ((4 + 2) /2) x 5 = 15
    The area is 15 units squared
    (I used area of a trapezoid)

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  17. I know that This shape is a trapezoid and that to find he area of a trapezoid the formula is :(B1+B2)/2xH=A
    B1=4units
    B2=2 units
    H=5units
    (4+2)/2x5=15
    This Trapezoid is 15 squared units.

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  18. Since this shape is a trapezoid I know that the formula is (b1+b2)xh/2. So I did 2(b1)+4(b)=6x5(height)=30/2=15. Therefore the area is 15unit2.

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  19. I know that this shape is a trapezoid.
    I know that the formula of a trapezoid is (((B1+B2)÷2)xh)=Area.
    (((B1+B2)÷2)xh)=Area
    (((4+2)÷2)x5)=Area
    ((6÷2)x5)=Area
    3x5=Area
    15=Area
    The area of the trapezoid is 15 units squared (15 units₂)

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  20. The area of this Trapezoid is 15units2.
    Though it is irregular, the formula for a trapezoid is still h(b1+b2/2)
    h=height=5units
    B1=higher base = 2units
    B2= lower base = 4units

    2+4=6
    6/2=3
    3*5= 15
    Back into a formula: 5(2+4/2)=15units2
    Therefore, the answer is that this trapezoid has the area of 15 units 2

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  21. To figure out this problem, I divided the shape into many smaller familiar shapes. I divided it into 3 triangles and a trapezoid. triangle one is having a length of 8 and width of 4. 8 * 4 = 24. 24/ 2 = 12, the area of triangle figure one is 12 u squared. triangle figure two has a dimension with the height of 7 and width of 3. 7 * 3 = 21, 21/2= 10.5. figure two has an area of 10.5 units squared. figure three was the last triangle with both its height and length being 2cm. 2*2= 4 4/2= 2 units squared. figure thre has 2 units squared of area. unit for is a trapezoid. there is a triangle in it with the area of half a unit squared ( I did this in my head for all portions of the figures 3 and 4) and a square figure with the area of 1 unit. this adds up to a total of 1.5 units squared for figure 4. then I add them all up to get the total area. 16 + 10.5 = 26.5. 26.5 + 1.5= 28 + 2 = 30 units squared. 30 units squared is the total area of the shape. looking at the other answers, I probably should have divided it by two, but I have no reason to do so, and I cannot cheat my way to the correct answer.

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