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Considering that last POTW question was not particularly challenging, please also complete the above question. Happy Valentine's Day and Family Day long weekend!
Mr. Gee's best choice would be to buy 2 Variety Pack Cs and 6 Variety Pack As. This is because after trying many combinations I found out this ended up being the most cost efficient method. Some other examples that meet the requirements are: 2 Bs and 4 As= $26.10 1 B, 1 C, and 5 As = $25.70 2 Cs and 6 As = $25.30 (My way) Therefore, Mr. Gee should by 6 Variety Pack As, 0 Variety Pack Bs and 2 Variety pack Cs.
Mr. Gee should get 2 pack C's and 6 A's. I know this because I know that in pack C, it is exactly the same as pack a, only the inclusion of the white chocolate bars makes it more expensive. Therefore i have to find the price of one white chocolate bar in pack C. The price would be $0.61 per white chocolate bar. Then I check the price of the Variety pack B and noticed that you get more bang for your buck in terms of milk chocolate bars and dark chocolate bars making it seem as the best option. The only problem is once you meet the maximum needed white chocolate bars, you would have to keep buying pack A's to fill the rest of the milk chocolate and dark chocolate required. Without writing it on paper I realized that it would cost more to get 2 Pack B's and 4 A's. So then I knew that getting 2 pack C's and 6 A's is the best option, just by looking at it. Then I calculated the price and found that it was $25.30. Knowing that the price to buy it would cost more than $25, I knew that this is the only effective option.
Mr. Gee would get the most "bang for his buck" if he bought 6 A's and 2 C's. I found this because I assumed that the more expensive variety pack would save you the most money, I also assumed that the best way to do this question would to only buy the exact amount of chocolate you would need. So I started with the largest variety pack (C), to get the six white chocolate bars needed, you would be 2 of these packs. You would now need 16 milk chocolate bars, and 1 dark chocolate bar, therefore you would buy pack A. In the end you would have a total of $25.30.
I started off with 2 Pack Bs, which was worth $15.20 and contained 8 milk chocolates, 4 dark chocolates, and 6 white chocolates, leaving me with 8 milk chocolates and 4 more dark chocolates to buy. Next, I used 4 Pack As to get the rest of the chocolates, which was worth $10.80 and contained 8 milk chocolates and 4 dark chocolates. Therefore, the lowest price would be $26.00.
If we buy 2 Pack C's - we get 9.10 and 4 milk, 2 dark, and all the white bars and 3 Variety B packs will fill the rest.
ReplyDeleteTherefore,
7.65 x 3 + 4.55 x 2
16 milk 8 dark and 6 white
ReplyDelete2 b 4 a
16 milk 8 dark 6 white
for 18 dollars
Brian, that's not 18 dollars...
DeleteI think you forgot to add one Variety Pack B
DeleteYea
DeleteMr. Gee's best choice would be to buy 2 Variety Pack Cs and 6 Variety Pack As. This is because after trying many combinations I found out this ended up being the most cost efficient method. Some other examples that meet the requirements are:
ReplyDelete2 Bs and 4 As= $26.10
1 B, 1 C, and 5 As = $25.70
2 Cs and 6 As = $25.30 (My way)
Therefore, Mr. Gee should by 6 Variety Pack As, 0 Variety Pack Bs and 2 Variety pack Cs.
Mr. Gee should get 2 pack C's and 6 A's. I know this because I know that in pack C, it is exactly the same as pack a, only the inclusion of the white chocolate bars makes it more expensive. Therefore i have to find the price of one white chocolate bar in pack C. The price would be $0.61 per white chocolate bar. Then I check the price of the Variety pack B and noticed that you get more bang for your buck in terms of milk chocolate bars and dark chocolate bars making it seem as the best option. The only problem is once you meet the maximum needed white chocolate bars, you would have to keep buying pack A's to fill the rest of the milk chocolate and dark chocolate required. Without writing it on paper I realized that it would cost more to get 2 Pack B's and 4 A's. So then I knew that getting 2 pack C's and 6 A's is the best option, just by looking at it. Then I calculated the price and found that it was $25.30. Knowing that the price to buy it would cost more than $25, I knew that this is the only effective option.
ReplyDeleteMr. Gee would get the most "bang for his buck" if he bought 6 A's and 2 C's. I found this because I assumed that the more expensive variety pack would save you the most money, I also assumed that the best way to do this question would to only buy the exact amount of chocolate you would need. So I started with the largest variety pack (C), to get the six white chocolate bars needed, you would be 2 of these packs. You would now need 16 milk chocolate bars, and 1 dark chocolate bar, therefore you would buy pack A. In the end you would have a total of $25.30.
ReplyDeleteI started off with 2 Pack Bs, which was worth $15.20 and contained 8 milk chocolates, 4 dark chocolates, and 6 white chocolates, leaving me with 8 milk chocolates and 4 more dark chocolates to buy. Next, I used 4 Pack As to get the rest of the chocolates, which was worth $10.80 and contained 8 milk chocolates and 4 dark chocolates. Therefore, the lowest price would be $26.00.
ReplyDelete2 pack C's and 6 A's= $25.30 #lowestprice
ReplyDeleteCongrats to Pipko, DNJMMIII, Leon, and Leo!
ReplyDeleteMr. Gee should purchase 6 Variety Pack A's and 2 Variety Pack C's for a total cost of $25.30.