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To find the area of quadrilateral BCDF, the best possible way is to subtract the area of the triangle from the 12cm by 12cm square.
To do so, we must find the area of the square: 12cm x 12cm = 144cm2
For the triangle: The base of the triangle must be half of the square; 6cm, and the height is the same length of the square making it 12cm. 12cm x 6cm = 72/2 = 36cm2
Subtraction: 144cm2 - 36cm2 = 108cm2 The area of quadrilateral BCDF is 108cm2
First, find the area of triangle FED ((6cm*12cm)/2=36cm2) and subtract that from the area of square BCDE (12cm*12cm=144cm2)and you get the area of quadrilateral BCDF (144-32=112), 112cm2.
To find the area of the quadrilateral BCDF you just need to take away the triangle in the square. First you need to calculate the area of the square which is 144cm (12cm x 12cm). Now the base of the triangle seems to be half of the base of the square so the base of triangle is 6 since the base of the square is 12. Next the height is the same so 12 x 6 equals 72 divided by 2 to get the area is 36 cm 2. The area of the quadrilateral BCDF is 36cm 2.
To find the area of the quadrilateral, I first looked at the information given, and found that triangle FED = triangle ABF. Upon closer examination of the square, I estimated that triangle FED = 1/4 of the square. The square is 12cm by 12cm, ( all side lengths are the same), and so, I calculate the area of the square: 12 X 12 = 144cm squared. 144 / 4 = 36cm squared 36 X 3 = 108cm squared The area of the quadrilateral BCDF is 108cm squared.
In order to find the area of BCDF, we can deduct the area of FED from the area of the square to find the answer.
First, l calculated the area of the square BCDE. Since it stated that the square has sides of 12cm length, and that a square has 4 equivalent sides, we can do 12cm x 12cm to get 144 cm2 as the area. In order to find the area of the triangle FED, we know that FE is 1/2 of the side length 12cm (6cm) and that ED is 12 cm, we can use the formula BxH/2= Area to find the triangle and subtract it to get BCDF.
12cm x 6cm/2= 72/2= 36cm.
Subtract square from Triangle FED: 144cm2 - 36cm2= 108cm2.
The answer is 108cm2 is the area of BCDF. With the given measurement and details of the question we can automatically assume the following: Because line AD visibly bisects line BE, Line BF and Line EF are both 6cm Line ED and Line AB are equal length because the area of ACD and BCDE are the same. The area of BCDE is given by 12*12= 144cm2 because it is stated tat side lengths equal 12cm. Area of triangle ABF is equal to FED triangle. FED'area is given by 6*12/2= 36cm2. BCFD is just BCDE area-FED area or 144cm2-36cm2=108cm2 Therefore i got the answer BCDF=108cm2
I first found the area of BCDE, which is 144cm2. Then find the area of FED, which would be 36cm2. Then I just subtracted FED from BCDE, which is 108. Therefore, the area of BCDF is 108cm2.
First, i founde the area of BCDE. 12 * 12 = 144cm2. The width of the triangle seems to be half of the side lengths for BCDE. 12 * 6= 72/2= 36cm2. then i take away the area of DEF from BCDE. 36 - 144= 108 cm2. The trapezoid of BCDF area is 108cm2.
First, I found the area of SQUARE BCDE. Because one side is 12 cm, all sides are 12 cm, therefore the area is: 12 x 12 = 144 cm2 I then found the area of TRIANGLE DEF. Visually, it looked like the side length EF was half of one side length on the square. Therefore, it's length is 6 cm. (12 x 6)/2 = 36 cm2. Because TRIANGLE DEF is taken away from SQUARE BCDE to make the QUADRILATERAL BCDF, I subtracted their areas: 144 - 36 = 108 cm2. Therefore, the area of QUADRILATERAL BCDF is 108 cm2.
To find the answer you had to subtract triangle FED from BCDE. The area of BCDE is 12x12=144 squared. To find the area of a triangle you do BxH/2. 6x12/2=36 squared Then you do 144-36=108cm2 So the area of the trapezoid BCDF is 108cm2.
To find the answer you have to subtract the area the triangle FED from BCDE. So first I found the area to BCDE. 12x12=144cm2 Then I found the area to triangle FED. 12x6/2=36cm2. Then I subtracted FED from BCDE. 144-36=108cm2 BCDF=108cm2
To find the area of quadrilateral BCDF, the best possible way is to subtract the area of the triangle from the 12cm by 12cm square.
ReplyDeleteTo do so, we must find the area of the square:
12cm x 12cm = 144cm2
For the triangle:
The base of the triangle must be half of the square; 6cm, and the height is the same length of the square making it 12cm.
12cm x 6cm = 72/2 = 36cm2
Subtraction:
144cm2 - 36cm2 = 108cm2
The area of quadrilateral BCDF is 108cm2
First, find the area of triangle FED ((6cm*12cm)/2=36cm2) and subtract that from the area of square BCDE (12cm*12cm=144cm2)and you get the area of quadrilateral BCDF (144-32=112), 112cm2.
ReplyDeleteTo find the area of the quadrilateral BCDF you just need to take away the triangle in the square. First you need to calculate the area of the square which is 144cm (12cm x 12cm). Now the base of the triangle seems to be half of the base of the square so the base of triangle is 6 since the base of the square is 12. Next the height is the same so 12 x 6 equals 72 divided by 2 to get the area is 36 cm 2.
ReplyDeleteThe area of the quadrilateral BCDF is 36cm 2.
To find the area of the quadrilateral, I first looked at the information given, and found that triangle FED = triangle ABF. Upon closer examination of the square, I estimated that triangle FED = 1/4 of the square.
ReplyDeleteThe square is 12cm by 12cm, ( all side lengths are the same), and so, I calculate the area of the square:
12 X 12 = 144cm squared.
144 / 4 = 36cm squared
36 X 3 = 108cm squared
The area of the quadrilateral BCDF is 108cm squared.
In order to find the area of BCDF, we can deduct the area of FED from the area of the square to find the answer.
ReplyDeleteFirst, l calculated the area of the square BCDE. Since it stated that the square has sides of 12cm length, and that a square has 4 equivalent sides, we can do 12cm x 12cm to get 144 cm2 as the area. In order to find the area of the triangle FED, we know that FE is 1/2 of the side length 12cm (6cm) and that ED is 12 cm, we can use the formula BxH/2= Area to find the triangle and subtract it to get BCDF.
12cm x 6cm/2= 72/2= 36cm.
Subtract square from Triangle FED:
144cm2 - 36cm2= 108cm2.
The area of the figure BFCD is 108cm2.
Hard copy
ReplyDeleteThe answer is 108cm2 is the area of BCDF.
ReplyDeleteWith the given measurement and details of the question we can automatically assume the following:
Because line AD visibly bisects line BE, Line BF and Line EF are both 6cm
Line ED and Line AB are equal length because the area of ACD and BCDE are the same.
The area of BCDE is given by 12*12= 144cm2 because it is stated tat side lengths equal 12cm.
Area of triangle ABF is equal to FED triangle.
FED'area is given by 6*12/2= 36cm2.
BCFD is just BCDE area-FED area or 144cm2-36cm2=108cm2
Therefore i got the answer BCDF=108cm2
I first found the area of BCDE, which is 144cm2. Then find the area of FED, which would be 36cm2. Then I just subtracted FED from BCDE, which is 108.
ReplyDeleteTherefore, the area of BCDF is 108cm2.
I did mine hard copy
ReplyDeleteFirst, i founde the area of BCDE. 12 * 12 = 144cm2. The width of the triangle seems to be half of the side lengths for BCDE. 12 * 6= 72/2= 36cm2. then i take away the area of DEF from BCDE. 36 - 144= 108 cm2. The trapezoid of BCDF area is 108cm2.
ReplyDeleteMy work was done hard copy, but my answer was: The area of trapezoid BCDF is 108cm2.
ReplyDeleteFirst, I found the area of SQUARE BCDE. Because one side is 12 cm, all sides are 12 cm, therefore the area is:
ReplyDelete12 x 12 = 144 cm2
I then found the area of TRIANGLE DEF. Visually, it looked like the side length EF was half of one side length on the square. Therefore, it's length is 6 cm.
(12 x 6)/2 = 36 cm2.
Because TRIANGLE DEF is taken away from SQUARE BCDE to make the QUADRILATERAL BCDF, I subtracted their areas:
144 - 36 = 108 cm2.
Therefore, the area of QUADRILATERAL BCDF is 108 cm2.
To find the answer you had to subtract triangle FED from BCDE.
ReplyDeleteThe area of BCDE is 12x12=144 squared.
To find the area of a triangle you do BxH/2.
6x12/2=36 squared
Then you do 144-36=108cm2
So the area of the trapezoid BCDF is 108cm2.
To find the answer you have to subtract the area the triangle FED from BCDE.
ReplyDeleteSo first I found the area to BCDE.
12x12=144cm2
Then I found the area to triangle FED.
12x6/2=36cm2.
Then I subtracted FED from BCDE.
144-36=108cm2
BCDF=108cm2