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Total area is 560cm^2 There are 7 rectangles 560cm^2/7=80cm^2' is the area The long side is 5x of the short side A x 5A = 80 6A=80 A=80/6 A=13.33333333... 13.3333333...cm by 66.66666...cm are the dimesions
First, I found the total area of one rectangle and b: a = width b = length ab = 560/7 = 80 560 = b^2 + 2ab a = 80/b, b = 80/a 560 = 6400/a^2 + 1600/a 560 = b^2 + 2 80/b = b^2 + 160 b^2 = 400 b = 20 Next, I found the value of a: 80/20 = 4 Therefore, 20 cm by 4 cm are the dimensions.
If the image is to scale, the width of the small rectangle should be one fifth of it's length. Since 560cm² is the total area of the seven triangles, one triangle would be 80cm² or 560cm²/7. I tried different combinations: 1*80, 2*40, 4*20, 5*16, and 8*10. Only 4*20 has the width one fifth of it's length (20/4=5).(Kind of a cheap way but it works).
First i found the area of each small rectangle, to do that i divided 560 by 7 to get 80. Then to find the dimensions, i knew that 5 times the width of the rectangle would equal the length as seen from the picture, i also knew that width x length had to be 560, so i used guess and check to find the factors of 80. I started of with 2x40, as i knew 1x80 wouldnt work(1x5 will never equal 80), and 2x5 did not equal 80, next i went up and did 4x20 as 3 didnt go into 80. 4x5=20 which is what needed to happen fro the dimensions to be correct. Therefore the dimensions of the smaller rectangles are all 4x20
First, I found the are of the small rectangles by dividing 560 by 7 (as all rectangles are identical) to get 80. therefore, the area of a small rectangle is 80 cm2. to find the dimensions of the smaller rectangle, I listed down the factor pairs of 80 which was 1 x 80, 2 x 40, 4 x 20, 5 x 16, 8 x 10. the dimensions 4x20 seemed like the most logical choice. so the L of the rectangle is 20cm and the W is 4cm
The total area is 560cm squared. The 7 smaller rectangles are all equal size, so 560/7=80cm squared. The most logical possible dimensions of the smaller rectangles would have to be 4cmx20cm.
I can't wait to try this one and finally get it published!
ReplyDeleteTotal area is 560cm^2
ReplyDeleteThere are 7 rectangles
560cm^2/7=80cm^2'
Total area is 560cm^2
ReplyDeleteThere are 7 rectangles
560cm^2/7=80cm^2' is the area
The long side is 5x of the short side
A x 5A = 80
6A=80
A=80/6
A=13.33333333...
13.3333333...cm by 66.66666...cm are the dimesions
First, I found the total area of one rectangle and b:
ReplyDeletea = width b = length
ab = 560/7 = 80
560 = b^2 + 2ab
a = 80/b, b = 80/a
560 = 6400/a^2 + 1600/a
560 = b^2 + 2 80/b
= b^2 + 160
b^2 = 400
b = 20
Next, I found the value of a:
80/20 = 4
Therefore, 20 cm by 4 cm are the dimensions.
560/7=80
ReplyDeleteEach small rectangle has a area of 80^2
W=80/L L=80/W
The answer is that the W and L must mutiply to get 80
20x4=80
Therefore: L:20, W:4
If the image is to scale, the width of the small rectangle should be one fifth of it's length. Since 560cm² is the total area of the seven triangles, one triangle would be 80cm² or 560cm²/7. I tried different combinations: 1*80, 2*40, 4*20, 5*16, and 8*10. Only 4*20 has the width one fifth of it's length (20/4=5).(Kind of a cheap way but it works).
ReplyDeleteFirst i found the area of each small rectangle, to do that i divided 560 by 7 to get 80. Then to find the dimensions, i knew that 5 times the width of the rectangle would equal the length as seen from the picture, i also knew that width x length had to be 560, so i used guess and check to find the factors of 80. I started of with 2x40, as i knew 1x80 wouldnt work(1x5 will never equal 80), and 2x5 did not equal 80, next i went up and did 4x20 as 3 didnt go into 80. 4x5=20 which is what needed to happen fro the dimensions to be correct. Therefore the dimensions of the smaller rectangles are all 4x20
ReplyDeleteAre is 560cm squared and 7 rectangles
ReplyDelete560/7=80
4x20 are the only reasonable dimensions for each small rectangle
First, I found the are of the small rectangles by dividing 560 by 7 (as all rectangles are identical) to get 80. therefore, the area of a small rectangle is 80 cm2. to find the dimensions of the smaller rectangle, I listed down the factor pairs of 80 which was 1 x 80, 2 x 40, 4 x 20, 5 x 16, 8 x 10. the dimensions 4x20 seemed like the most logical choice. so the L of the rectangle is 20cm and the W is 4cm
ReplyDeleteEntire Area is 560cm squared
ReplyDelete560cm^2 ÷7= 80cm^2(Area of each small rectangle)
Only reasonable dimensions for the rectangle is 4x20
The total area is 560cm squared.
ReplyDeleteThe 7 smaller rectangles are all equal size, so 560/7=80cm squared.
The most logical possible dimensions of the smaller rectangles would have to be 4cmx20cm.